Answer:
Account for the following a the ionic radius of fluoride ion F is 136 pm while the atomic radius of fluorine F is only 64 pm
The size of an anion will be larger than that of the parent atom because the addition of one or more electrons would result in increased repulsion among electrons and decrease in effective nuclear charge. This the ionic radius of fluoride ion (F–) is 136 pm whereas atomic radius of Fluorine (F) is only 64 pm.
Explanation:
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