a gas is insulated thermally and then allowed to expand against a constant pressure from v1 to v2 .then
Answers 2
Answer:
-505 J
Explanation:
The change in the internal energy is given by the following expression.
ΔU=q+W
Since container is well insulated, q=0.
Hence, ΔU=W=−PΔV
ΔU=W=−2.5atm×(4.50L−2.50L)
ΔU=W=−5.0Latm
Convert the unit to J
ΔU=W=−5.0Latm×1Latm101.33J=−505J
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Author:
libbyzkjm
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The change in the internal energy is given by the following expression.
The change in the internal energy is given by the following expression.ΔU=q+W
The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.
The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔV
The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)
The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0Latm
The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0LatmConvert the unit to J
The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0LatmConvert the unit to JΔU=W=−5.0Latm×1Latm101.33J=−505J
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halle6rbe
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