the number of moles present in 48 lit of O2 at STP is​

Answers 2

Answer:

1.5 moles

Explanation:

Moles=  

molecular weight

Weight

 

Molecular weight of O  

2

=32g/mol

Moles=  

32

48

 =1.5 moles

Given,

The volume of O₂ gas at STP = 48L

To find,

The number of moles of O₂ at given conditions

Solution,

At STP, the pressure is 1 atm and the temperature is 273K. The proportionality constant, R, is equal to 0.0821 [tex]\frac{L * atm}{mol * K}[/tex]

Now, using the ideal gas law equation,

P × V = n × R × T

where,

  • P = Pressure (atm)
  • V = Volume (litre)
  • n = Number of moles
  • R = Universal gas constant ([tex]\frac{L * atm}{mol * K}[/tex])
  • T = Temperature (Kelvin)

Further, rearranging the ideal gas equation to get the number of moles

⇒ n = [tex]\frac{PV}{RT}[/tex]

Inserting values into the equation,

⇒ n = [tex]\frac{(1)(48) }{(0.0821)(273)}[/tex]

⇒ n = 2.14 moles

Hence, 48 litres of O at STP = 2.14 moles.

 

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