During change of N2 to N2- ion, the added electron goes to​

Answer:

cotton is exposed to the air or black carbon it turns into black

• The fine cotton thread-like structure is a member of kingdom fungi and its name is Rhizopus stolonifer.
• The branching fine cotton thread is called hyphae and all the hyphae are together known as mycelium.
• The bread mould forms spores inside a sporangium. When it breaks open, they germinate to form a new mould.
• The new mould appears black in colour.

Answer:

little messy but hope it helps

ans b

The second equation of motion can be defined as,

s = ut + (1/2) at²

where s is distance, t is time, u is initial velocity and a is the acceleration.

The velocity of projectile, V= (2î + 3j) m/s

The equation of trajectory.

Given, V= (2i + 3j) m/s

The velocity in the i direction is 2i m/s.

The distance traveled in the i direction, that is in the x-axis, acceleration is zero in the x-axis,

s = ut + (1/2) at²

x = ut + (1/2) (0)t²

x = 2t m/s

The velocity in the j direction is 3j m/s.

The distance traveled in the j direction, that is in the y-axis, acceleration is 10m/s² in the downward y-axis,

s = ut + (1/2) at²

y = (3)t - (1/2) (10)t²

y = 3t - 5t²

So, writing x in terms of y,

y = (3/2)x - (5/4)x²

4y = 6x - 5x²

Hence, the equation of the trajectory is 4y = 6x - 5x²  and the correct option is (b) 4y = 6x - 5x².

#SPJ2

Answer:

here is your answer hope it helps

• Assuming the situation as a right angled triangle.
• His speed when he runs = 6 m/s ([tex]v_{m}[/tex]) in x-axis
• Angle of incline = 37 degrees w.r.t to the vertical
• Let the speed of rain be v[tex]_{r}[/tex] but w.r.t to man the speed of rain is v[tex]_{m}[/tex] (x axis) -v(y axis)

         tan 37° = [tex]\frac{6}{v}[/tex]

             [tex]\frac{3}{4} =\frac{6}{v} \\v= 8[/tex]

Therfore speed of rain = 6i - 8j

Total numerical value of speed of rain is [tex]\sqrt{6^{2}+8^{2}\\[/tex]

                                                                   [tex]\sqrt{36+64}[/tex]

                                                                  = 10 m/s

Answer:

Eight drops of mercury of equal radii possessing equal charges combine to from a big drop. Then the capacitance of bigger drop compared to each individual small drop is. As capacity is r, hence capacity becomes 2 times.