Highest occupied molecular orbital of B2+ ion is a) π*orbital b) Sigma* orbital c) π orbital d) Sigma orbital​

Answers 2

Answer:

pi orbital

Explanation:

bec there is weak pi bond that's why comparative sigma bond

Option (c) Highest occupied molecular orbital of [tex]B2+[/tex]ion is  π orbital

Explanation:

  • [tex]B2+[/tex]  has 10 electrons  
  • Its electronic configuration is [tex]sigma (1s), 2 sigma*(1s) ,2 sigma(2s), 2 sigma* (2s) ,2 pi (2p) x1, Pi 2p y1[/tex]
  • Here unpaired electrons are found and due to the presence of unpaired electrons, the nature is paramagnetic.
  • Here the highest occupied molecular orbital is of [tex]\pi[/tex] orbital.
  • pi bonds are covalent chemical bonds.
  • They can form a double and triple bonds but do not form single bonds.
  • They involve complete overlapping of two lobes of atomic orbital with the other.

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Comment on the tone of the speaker when she says ‘Will you please look at me when I’m speaking to you, Amanda!​

Answer:

The tone is an angry one.

Explanation:

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Answer:

A. Se

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Answer:

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A projectile is launched with initial velocity Vo= (2î + 3j) m's. The equation of trajectory of particle is (g = 10 m/s) a) y = 4x - 6x ^2b) 4y = 6x - 5x^2c) 4y = 3x - 10x^2 d)y = 4x - 5x^2​

Answer:

little messy but hope it helps

ans b

answer img
Concept:

The second equation of motion can be defined as,

s = ut + (1/2) at²

where s is distance, t is time, u is initial velocity and a is the acceleration.

Given:

The velocity of projectile, V= (2î + 3j) m/s

Find:

The equation of trajectory.

Solution:

Given, V= (2i + 3j) m/s

The velocity in the i direction is 2i m/s.

The distance traveled in the i direction, that is in the x-axis, acceleration is zero in the x-axis,

s = ut + (1/2) at²

x = ut + (1/2) (0)t²

x = 2t m/s

The velocity in the j direction is 3j m/s.

The distance traveled in the j direction, that is in the y-axis, acceleration is 10m/s² in the downward y-axis,

s = ut + (1/2) at²

y = (3)t - (1/2) (10)t²

y = 3t - 5t²

So, writing x in terms of y,

y = (3/2)x - (5/4)x²

4y = 6x - 5x²

Hence, the equation of the trajectory is 4y = 6x - 5x²  and the correct option is (b) 4y = 6x - 5x².

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