Write the value of 2.303 RT F in the nernst equation

Answers 1

Answer:

The value of [tex]\frac{2.303\ R\ T}{F}[/tex] in the Nernst equation is [tex]0.0592[/tex]·

Explanation:

We know that the Nernst Equation,

[tex]E_{(cell)}\ =\ E^0_{(cell)} \ -\ \frac{2.303\ R\ T}{n\ F}[/tex] log [tex]\frac{[Products]}{[Reactants]}[/tex]

where,

[tex]E_{(cell)}[/tex] [tex]=[/tex] The cell potential

[tex]E^0_{(cell)}[/tex] [tex]=[/tex] The standard cell potential

R [tex]=[/tex] The universal gas constant

T [tex]=[/tex] Temperature in kelvin

n [tex]=[/tex] The number of electrons

F [tex]=[/tex] Faraday's constant

Here, we want to find out the value of [tex]\frac{2.303\ R\ T}{F}[/tex] in the Nernst equation·

For that,

The value of R [tex]=[/tex] [tex]8.314\ J\ K^{-1}\ mol^{-1}[/tex]

The temperature we take as the standard value [tex]=[/tex] [tex]298[/tex] K

The value of F [tex]=[/tex] [tex]96500[/tex] C

On substituting these values in the expression we get,

⇒ [tex]\frac{2.303\ R\ T}{F}[/tex] [tex]=[/tex] [tex]\frac{2.303\ *\ 8.314\ *\ 298}{96500}[/tex]

⇒ [tex]\frac{2.303\ R\ T}{F}[/tex] [tex]=[/tex] [tex]0.0592[/tex]

Therefore,

The value of [tex]\frac{2.303\ R\ T}{F}[/tex] in the Nernst equation is [tex]0.0592[/tex]·

explain the formation of bakelite

Vachan badlo in marathi 1.बाक

Ramesh___(come) my home to meet me daily

Name the country which is Southernmost tip of the Brazil?