Find the class interval having class-mark 18 and class-size 10.​

Answer:

Class interval= 13-23

Explanation:

Let 1st no. oof the interval be x and the other be y.

we know,

x-y=10        (class size)

x+y/2 = 18      (class mark)

x+y = 36

by elimination method

2x = 46

x = 23

put value of x in any of above eq.

y= 13

The class interval having class-mark 18 and class-size 10 is 13 - 23

Given :

A class interval having class mark 18 and class size 10

To find :

The class interval

Concept :

Class Interval :

When the number of sample values are large in number and are in wide range, then the whole data is divided in a number of several groups according to the size of the sample. Each of these groups, made as above, is known as class interval

Solution :

Step 1 of 3 :

Write down the class mark and class size

Here it is given that the class interval is with class mark 18 and class size 10

Step 2 of 3 :

Calculate the upper class boundary and lower class boundary

Upper class boundary

[tex]\displaystyle \sf{ =Class \: mark + \frac{Class \: size }{2} }[/tex]

[tex]\displaystyle \sf{ = 18 + \frac{10 }{2} }[/tex]

[tex]\displaystyle \sf{ = 18 + 5 }[/tex]

[tex]\displaystyle \sf{ = 23 }[/tex]

Lower class boundary

[tex]\displaystyle \sf{ =Class \: mark - \frac{Class \: size }{2} }[/tex]

[tex]\displaystyle \sf{ = 18 - \frac{10 }{2} }[/tex]

[tex]\displaystyle \sf{ = 18 - 5 }[/tex]

[tex]\displaystyle \sf{ = 13}[/tex]

Step 3 of 3 :

Find the class interval

Lower class boundary = 13

Upper class boundary = 23

Hence the required class interval is 13 - 23

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