Vachan badlo in marathi 1.बाक​

Explanation:

प्रिय 'प्र' प्रकृति तथा भावार्थक 'इमन्' प्रत्यय से 'प्रेम' शब्द निष्पन्न हुआ है । इसलिए 'प्रेमन्' का अर्थ हुआ 'प्रियता' प्रिय का भाव या प्रिय होना । प्रेम शब्द की व्युत्पत्ति 'प्रीञ्' धातु और 'मनिन्' प्रत्यय को जोड़कर भी हो सकती है ।

उपर्युक्त शब्दों में 'प्र', 'प्रति', 'अधि', 'वि', 'अनु' और 'स्व' उपसर्ग हैं तथा 'चार', 'कूल', 'गम', 'हार', 'राग' और 'देश' मूल शब्द हैं।

Answer:

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Explanation:

hjjnjahdnusnnjsb js

Explanation:

Molded Bakelite forms in a condensation reaction of phenol and formaldehyde, with wood flour or asbestos fiber as a filler, under high pressure and heat in a time frame of a few minutes of curing. The result is a hard plastic material.

It is a thermosetting phenol-formaldehyde resin formed by the condensation reaction of phenol with formaldehyde. So, we can, in general, say that Bakelite is a condensation polymer or a phenolic resin. ... The reaction involved is condensation reaction in the presence of either a basic or acidic catalyst.

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Answer:

The value of  [tex]\frac{2.303\ R\ T}{F}[/tex] in the Nernst equation is [tex]0.0592[/tex]·

Explanation:

We know that the Nernst Equation,

  [tex]E_{(cell)}\ =\ E^0_{(cell)} \ -\ \frac{2.303\ R\ T}{n\ F}[/tex]   log  [tex]\frac{[Products]}{[Reactants]}[/tex]

where,

[tex]E_{(cell)}[/tex] [tex]=[/tex] The cell potential

[tex]E^0_{(cell)}[/tex] [tex]=[/tex] The standard cell potential

R [tex]=[/tex]  The universal gas constant

T [tex]=[/tex]  Temperature in kelvin

n [tex]=[/tex]  The number of electrons

F [tex]=[/tex]  Faraday's constant

Here, we want to find out the value of [tex]\frac{2.303\ R\ T}{F}[/tex] in the Nernst equation·

For that,

The value of R [tex]=[/tex] [tex]8.314\ J\ K^{-1}\ mol^{-1}[/tex]

The temperature we take as the standard value  [tex]=[/tex] [tex]298[/tex] K

The value of F  [tex]=[/tex] [tex]96500[/tex] C

On substituting these values in the expression we get,

⇒  [tex]\frac{2.303\ R\ T}{F}[/tex] [tex]=[/tex] [tex]\frac{2.303\ *\ 8.314\ *\ 298}{96500}[/tex]

⇒  [tex]\frac{2.303\ R\ T}{F}[/tex] [tex]=[/tex] [tex]0.0592[/tex]

Therefore,

The value of  [tex]\frac{2.303\ R\ T}{F}[/tex] in the Nernst equation is [tex]0.0592[/tex]·