Step-by-step explanation:
The positions of Ankur, Syed and David are represented as A, B and C respectively.As they are sitting at equal distances, the triangle is equilateralAD ⊥ BC is drawn. AD is the median of ΔABC and it passes through the centre O.O is the centroid of the ΔABC. OA is the radius of the triangle.
= 2/3 ADLet the side of a triangle a metres then BD = a/2 m.
AB2 =AD2
AB2 =AD2⇒ AD2 = AB2
⇒ AD2 = a2 -(a/2)2
⇒ AD2 = a2 -(a/2)2⇒ AD2 = 3a2/4
⇒ AD2 = a2 -(a/2)2⇒ AD2 = 3a2/4⇒ AD = √3a/2
⇒ AD2 = a2 -(a/2)2⇒ AD2 = 3a2/4⇒ AD = √3a/2OA = 2/3 AD
⇒ AD2 = a2 -(a/2)2⇒ AD2 = 3a2/4⇒ AD = √3a/2OA = 2/3 AD20 m = 2/3 × √3a/2
⇒ AD2 = a2 -(a/2)2⇒ AD2 = 3a2/4⇒ AD = √3a/2OA = 2/3 AD20 m = 2/3 × √3a/2a = 20√3 m
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________________________The length of the string of the toy is 20√3
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☘️,★________*[tex]\huge{{\underline{\underline{ \colorbox{lave}{\color{cyan}{BËFÎKRÃ♣}}}}}}[/tex]