(a+b) = 8, a² - b² = 32 then (a-b) = ?

Answers 2

Answer:

Answer is 4

Explanation:

Given :- a+b = 8

[tex]a {}^{2} - b {}^{2} = 32[/tex]

As we know

[tex]a {}^{2} - b {}^{2} = (a + b)(a - b)[/tex]

Substitute values

32 = (8) (a-b)

[tex](a - b) = \frac{32}{8} [/tex]

a - b = 4

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Answer:

(a+b)=8,a^2-b^2=32

(a+b)(a-b)=32

8(a-b)=32

(a-b)=32/8

(a-b)=4

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