Answer:
Force applied on brakes will be 3000 N
Explanation:
Given data,
mass of the car m = 1000 kg
initial velocity of the car u = 54 km/h
let us convert u in SI units
[tex]u = \frac{54 \times 1000m}{60 \times 60s} [/tex]
[tex]u = 54 \times \frac{5}{18} [/tex]
[tex]u = 3 \times 5 = 15m {s}^{ - 1} [/tex]
final velocity v = 0 as it stops.
time taken t = 5 s
from Newton's second law force is mass times acceleration
[tex]f = ma[/tex]
but
[tex]a = \frac{v - u}{t} [/tex]
[tex]f = m \times \frac{v - u}{t} [/tex]
substituting all values,
[tex]f = 1000 \times \frac{0 - 15}{5} [/tex]
[tex]f = 1000 \times ( - 3)[/tex]
[tex]f = - 3000 [/tex]
Thus force applied on brakes will be 3000 N. here negative sign indicates force applied against direction of motion of body.