describe the role of construction industry in national development​

Answer:

Tea and Coffee are considered cash crops because they are primarily grown for the purpose of profits, they are also a large part of India's exports. They cannot be consumed by the farmers directly because they are not food crops.

Answer:

Tea and Coffee are considered cash crops because they are primarily grown for the purpose of profits, they are also a large part of India's exports. They cannot be consumed by the farmers directly because they are not food crops.

Explanation:

Tea and coffee are cash crops as they are mainly grown for sale. They are hot beverages consumed by people around the world. It is a non-food crop as we drink them for refreshing ourself and not because it is a compulsion.

Some collective nouns are used for more than one animal. For example, both Bats and Ants can be found in a 'Colony'.

Explanation:

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Answer:

Collective Noun for Bat's is Colony.

Explanation:

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Explanation:

The finite automata or finite state machine is an abstract machine which have five elements or tuple. It has a set of states and rules for moving from one state to another but it depends upon the applied input symbol. Basically it is an abstract model pf digital computer. Following figure shows some essential features of a general automation.

Input

Output

States of automata

State relation

Output relation

It is a powerful model which was proposed by Alan Turing in 1936. The earlier models like finite automata and push-down automata are bot considered as the accurate models because they cannot recognize simple language. But the turing machine is the most accurate model for the personal computers. A turing machine is capable of solving every problem that a real computer can do. There are also some problems which can not be solved by turing machine because these problems are beyond the theoretical limits of computation.

Finite Automata Turing Machine

It recognize the language called regular language. It will recognize not only regular language but also context free language, context sensitive language and recursively enumerable languages.

In this the input tape is of finite length from both left and right side. In this the input tape is of finite length from left but is of infinite length from right.

It consists of finite number of states, finite set of input symbols, initial state of automata and finite set of transition rules for moving from one state to another. It also contains finite set of tape symbols and a blank symbol on the tape in addition to finite number of states, finite set of input symbols, initial state of automata and finite set of transition rules for moving from one state to another.

In this head is able to move in right direction only. In two way automata, head is able to move in both directions. In this, head can move in both directions.

Head is only able to read the symbols from the tape but can not write symbols on the tape. Head is able to read as well as write symbols on the tape.

It is weak as compare to Turing Machine. It is powerful than Finite Automata.

Designing finite automata is easier. Designing turing machine is difficult and as well as complex.

The transition function in finite automata can be represented by :

δ : Q × Σ* → Q The transition function in turing machine can be represented by :

δ : Q × T → Q × T × {L, R}

where L and R specifies the left and right movement of tape head.

Answer:

O is the centre of the circle.

CD is the diameter, CD = 5 cm

EF is the chord parallel to CD, EF = 3 cm

OG is perpendicular drawn on EF from O.

In ΔOGE we have,

∠OGE = 90° [∵ OG is perpendicular on EF]

OE = 5/2 = 2.5 cm [∵ Diameter = 5 cm]

EG = 3/2 = 1.5 cm [∵perpendicular drawn from centre bisects chord]

∴ Area of the quadrilateral,

= 8 cm2

The answers are Radius of circle 5 cm

               Area of Quadrilateral  = 20 cm²

Given: Bottom side of the quadrilateral is diameter of the circle

From given picture bottom of the quadrilateral AB = 10cm

and CD = 6 cm

To find: Radius of the circle and area of the quadrilateral

Solution:

a) Radius of circle

given that diameter of circle = bottom of quadrilateral  

⇒ diameter of circle 2r = 10 cm

⇒ Radius of circle r = 10/2 = 5 cm

∴ Radius of circle 5 cm

b) Area of the quadrilateral

Draw a line by joining mid points of AB and CD

and join mid point of AB and vertice C then a right angle triangle POC  is formed as show figure

In triangle POC  ⇒  OC² = OP²+ PC²  

[ here OC = radius = 5 cm and PC = [tex]\frac{1}{2} (CD)[/tex] = 3 cm ]

⇒  5 ² = OP²+ 3²  

⇒ OP² = 5² - 3² = 25 - 9 = 16

⇒ OP² = 4²

⇒ OP = 4  is the altitude/height of trapezium

Therefore, area of trapezium =  [tex]\frac{1}{2} (base)(height)[/tex]  

⇒ [tex]\frac{1}{2} (10)(4)[/tex] = 5(4) = 20 cm²

∴ Area of triangle = 20 cm²

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