Who led the movement called Nyaya Yudh?​

Answer:

Child Marriage In many states of our country including Delhi, child marriages at the age of below 10 years are taking place. Our samiti is working for eradication of such type of marriages. Under this program one telecast was made on INDIA TV on 4th and 5th of January, 2006.

The Samiti has a regular program for providing basic education to the adults.

Help for Poor every year poor and meritorious students are selected from various schools and awarded scholarship

Study Material to Poor Students Books, copies etc. are distributed to poor students of slum areas.

Free Medical Care  A free medical Centre for the residents of slum area is run. Free consultation and medicines are provided to the needy people.

Answer:

the host of issues in survivorship. Others want to distance themselves from the “world of cancer.” Studies also show that enrollment in cancer support groups improved quality of life for selected patients. Women tend to enroll at higher numbers than men. Enrollment also varies widely among different cancers, with breast cancer the highest. Then there are the cultural and religious aspects that affect patient perspectives on sharing their stories with others.

Thus, writin

Explanation:

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Answer:

Santiago’s survival story

Explanation:

The four siblings of 14-year-old Santiago are E.J., Amiel, Princess, and Gerardo. His lone sister, Princess, who is 4 years old, is his favourite. Her eyes sparkle when she smiles. Princess agrees that Santiago is her favourite.

She explains, "I love him because he constantly looks out for me and feeds me.

Santiago's family moved in with his grandparents as Typhoon Haima approached the Philippines. However, Santiago claims that when the storm grew worse, "my father and my grandfather had to tear down the plywood at the rear of his house for us to leave.

The next day, when we looked on our house, "I could not detect a trace of it," he claims. Our belongings were submerged in floodwater, and all of my school supplies and books were destroyed.

Santiago breaks down and sobs as he recalls their close call and their losses.

However, aid reached Solana three days after Super Typhoon Haima devastated Northern Luzon.

In addition to kitchen sets, blankets, mosquito nets, and hygiene packages with toothbrushes, toothpaste, laundry detergent, and bath soap, families who had practically lost everything, like Santiago's, also received these supplies.

Elena, Santiago's mother, tells me, "We've witnessed the best of people's compassion in the previous days. While you, from Manila, arrived to provide us relief supplies, my husband's boss welcomed us into their home without expecting anything in return.

In their neighbourhood, her family was the first to get aid supplies.

Following them from the World Vision distribution centre to their lodging was a pleasure for me. While the rest of the family gathered around to see what they had received, Princess eagerly unwrapped boxes.

Were they content? They were, indeed. Was I content? Oh yes.

This kind of situation is the pinnacle of my career. Emergency communications can't be adapted to, which is a good thing. It will always be a mixture of sorrow and appreciation, agony and delight.

Answer:

Answer:

\sin30^\circ+ \cos 45\circ+ \tan 180^\circ=\frac{\sqrt2+2}{2\sqrt2}sin30

∘

+cos45∘+tan180

∘

=

2

2

2

+2

Step-by-step explanation:

Given : Expression \sin30^\circ+ \cos 45\circ+ \tan 180^\circsin30

∘

+cos45∘+tan180

∘

To find : Evaluate the expression ?

Solution :

We know the values of trigonometric terms like,

\sin30^\circ=\frac{1}{2}sin30

∘

=

2

1

\cos 45\circ=\frac{1}{\sqrt2}cos45∘=

2

1

\tan 180^\circ=0tan180

∘

=0

Substitute the values in the expression,

\sin30^\circ+ \cos 45\circ+ \tan 180^\circsin30

∘

+cos45∘+tan180

∘

=\frac{1}{2}+\frac{1}{\sqrt2}+0=

2

1

+

2

1

+0

=\frac{\sqrt2+2}{2\sqrt2}=

2

2

2

+2

Therefore, \sin30^\circ+ \cos 45\circ+ \tan 180^\circ=\frac{\sqrt2+2}{2\sqrt2}sin30

∘

+cos45∘+tan180

∘

=

2

2

2

+2

Step-by-step explanation:

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Answer:

The force of gravitation between two objects of masses 50 kg and 120 kg respectively kept at a distance of 10 m from one another is 400.2 × 10⁻¹¹ N.

The force of gravity on a body of mass 150 kg lying on the surface of the earth is 1465.5 N.

Explanation:

1) Two objects of masses 50 Kg and 120 Kg.

∴ M = 120 Kg

   m = 50 Kg

Distance of separation, d = 10 m

Force of gravitation, F = G Mm / d²

                                     = (6.67 × 10⁻¹¹ × 120 × 50) / (10²)

                                     = 400.2 × 10⁻¹¹ N

2) Mass of the body, m = 150 Kg

Mass of the earth, M = 6 × 10²⁴ Kg

Distance of separation will be equal to the radius of the earth since the body is lying on the surface of the earth.

∴ d = Radius of the earth, R = 6.4 × 10⁶ m

Force of gravitation, F = G Mm / d²

                                     = (6.67 × 10⁻¹¹ × 6 × 10²⁴ × 150) / (6.4 × 10⁶)²

                                     = 1465.5 N