Two objects of mass 4 kg and 10 kg are seperated by 2 m is vacuum. Find gravitation force acting between them?
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Subject:
Science -
Author:
siennaaok7 -
Created:
1 year ago
Answers 2
Answer:
Gravitational force = 6.673×10⁻¹⁰ N
Explanation:
If two objects A and B of masses 'M' and 'm' lie at a distance 'd' from each other, and the force of attraction between the two objects is 'F', according to the universal law of gravitation:
- The force between the two objects is directly proportional to the product of their masses,
F ∝ M×m
- And the force between two objects is inversely proportional to the square of the distance between them.
F ∝ 1/d²
- Which forms the equation:
F = GMm/d²,
where G = 6.673×10⁻¹¹ N m² kg⁻² is the universal gravitational constant.
Step 1:Given:
Mass of one object, M = 4 kg
And the mass of the other object, m = 10 kg
They are separated by a distance, d = 2 m
The gravitational constant, G = 6.673×10⁻¹¹ N m² kg⁻²
Step 2:Substituting the above values into the equation of law of gravitation:
[tex]F=\frac{GMm}{d^{2} }[/tex]
[tex]F=\frac{(6.673)10^{-11} (4)(10)}{2^{2} }[/tex]
⇒ F = 6.673×10⁻¹⁰ N
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Author:
quintinx4x9
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Rate an answer:
10
Mass of body a is Ma=2kg
Mass of body b is Mb=4kg
Mass of body cis Mc=1kg
Separation between a and b=2m
Let the body C be placed at a distance d fron the body A,
The gravitational force between A and C,
FAC=GMaMc/d^2=G*2*1/d^2=2G/d^2......1
the gravitational force between B and C is
FBC=GMbMc/d^2=G*4*1/(2-d)^2=4G/(2-d)^2
For body C the gravttatinal force =0
hence Fac=Fbc
2g/d^2=4G/(2-d)^2
(2-d)^2=2d^2
2-d=√2d
(√2+1)d=2
d=0.83m
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izayah
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