Explanation:
U1=80
Let “d” be common difference
U4=10
==> U4=U1+3d
{Since, in an Arithematic Sequence,
nth term =a+(n-1)d }
==> U4=80+3d
10=80+3d
==> d= (-70/3)
Hence we got first term U1=80, common difference d =(-70/3)
Now, U2= U1+d
U2= 80 + (-70/3)
U2 = (240–70)/3
U2 = 170/3
And
U3 = U1 + 2d
U3 = 80 + 2(-70/3)
U3 = (240–140)/3
U3 = 100/3
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