Subject:
ScienceAuthor:
lilianwxjlCreated:
1 year agoAnswer
Initial velocity u=0
Final velocity v=30m/s
Time, t=10sec
v=u+at
30=0+a×10
30=10a
a=
10
30
=3m/s
2
for next 10sec, initial velocity =30m/s
s=ut+
2
1
at
2
=30×10+
2
1
×3×(10)
2
=300+1.5×100
=300+150
=450m
Author:
inmaculadaf6au
Rate an answer:
9Answer:
945 cm
Explanation:
Given:-Initial Velocity, u = 300 cm/s
Acceleration, a = 10 cm/s²
Time taken, t = 3 s
To be calculated:-
Calculate the distance (s) travelled by a body .
Formula used:-
s = ut + 1/2 at²
Solution:-
From the second equation of motion,
s = ut + 1/2 at²
★ Putting the values in the above formula, we get
s = 300 × 3 + 1/2 × 10 × ( 3 )²
s = 900 + 5 × 9
s = 900 + 45
s = 945 cm
Thus, the distance travelled by a body is 945 centimeters.pls mark me as the brainliest
Author:
cale
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