Answer:
The correct option is 2) 9.8 kW
Explanation:
Here we have been given that water is pumped from a depth of 10 m and is delivered through a pipe that has a cross-section of [tex]10m^{2}[/tex]
It is to deliver a volume of 10 m per second.
The power for the water pump is given by:
Power = mgh
where m is the mass of the water needed to be drawn above, g is the acceleration due to the gravity and h is the height to which the water has to be pumped up.
m = density (d) × volume (V)
d = 1000 kg/[tex]m^{3}[/tex]
V = [tex]10^{-1}[/tex] [tex]m^{3}[/tex]
m = 1000 kg/ [tex]m^{3}[/tex] × [tex]10^{-1}[/tex] [tex]m^{3}[/tex]
⇒ m = 100 kg
g = 9.8 m/[tex]s^{2}[/tex]
h = 10 m
Therefore, the power required for the pump is as below;
P = mgh
⇒ P = 100 kg × 9.8 m/[tex]s^{2}[/tex] × 10 m
⇒ P = 9.8 kW
Therefore the correct option is option 2) 9.8 kW