Subject:
ScienceAuthor:
robertoobrienCreated:
1 year agoExplanation:
Given counter sequence is: 0 – 1 – 0 – 2 – 0 -3
There are three transition from 0 to 1, 2 and 3.
To differentiate with these transitions, we require 2 bits.
Sequence will be like 00 – 01 – 00 -10 – 00 – 11
Now again we need 2 more bits to differentiate between these 3 0’s.
0000 – 0001 – 0100 – 0010 – 1000 – 0011
Total 4 bits are needed; 4 minimum flip flops are needed to implement this counter.
Author:
emmyjoseph
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2Concept Introduction:-
It is a type of branch in which maths are deals with their own properties and also manipulation of numbers.
Given:-
We have been given a sequence.
To Find:-
We have to find their repeats.
Solution:-
According to the problem
Given counter sequence is: 0 – 1 – 0 – 2 – 0 -3
There are three transition from 0 to 1, 2 and 3.
To differentiate with these transitions, we require 2 bits.
Sequence will be like 00 – 01 – 00 -10 – 00 – 11
Now again we need 2 more bits to differentiate between these 3 0’s.
0000 – 0001 – 0100 – 0010 – 1000 – 0011
Total 4 bits are needed; 4 minimum flip flops are needed to implement this counter.
Final Answer:-
The final answer is 4
#SPJ2
Author:
nathan437
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9