Waves are rhythmic disturbances that carry energy through matter or space without transferring

Step-by-step explanation:

∵ Mode = 38.

∴ The modal class is 30-40.

Mode =  l + f 1 − f 0 2 f 1 − f 0 − f 2 × h l+f1−f02f1−f0−f2×h

= 30 + 16 − 12 32 − 12 − x 16−1232−12−x x 10

= 38 4 20 − x 420−x x 10 = 8 8 (20 - x)

= 40 20 -

x = 5

X = 15

[tex]\large\underline{\sf{Solution-}}[/tex]

The frequency distribution table is

[tex]\begin{gathered} \begin{array}{|c|c|} \bf{Class \: Interval} & \bf{Frequency} \\ \\ 0 - 10 & 7   \\ \\10 - 20 & 9  \\ \\20 - 30 & 12  \\ \\30 - 40 & 16  \\ \\40 - 50 & x \\ \\50 - 60 & 6 \\ \\60 - 70 & 11 \end{array}\end{gathered} \\ [/tex]

Given that,

[tex]\rm \: Mode = 38 \\ [/tex]

[tex]\bf\implies \:Modal \: class \: = \: 30 - 40 \\ [/tex]

[tex]\rm \: f_0 = 12 \\ [/tex]

[tex]\rm \: f_1 = 16 \\ [/tex]

[tex]\rm \: f_2 = x \\ [/tex]

[tex]\rm \: h \: = \: 10 \\ [/tex]

[tex]\rm \: l \: = \: 30 \\ \\ [/tex]

We know, Mode for a continuous series is given by

[tex] \red{\boxed{ \boxed{\sf{Mode \: = \: l \: + \: \bigg(\dfrac{f_1 \: - \: f_0}{2f_1 \: - \: f_0 \: - \: f_2} \bigg) \: \times \: h }}}} \\ [/tex]

where,

l is lower limit of modal class.

[tex] \sf{f_1} [/tex] is frequency of modal class

[tex] \sf{f_0} [/tex] is frequency of class preceding modal class

[tex] \sf{f_2} [/tex] is frequency of class succeeding modal class

h is class height.

So, on substituting the values in above formula, we get

[tex]\rm \: \: 38= 30 + \bigg[\dfrac{16 - 12}{2 \times 16 - 12 - x} \bigg] \times 10\\[/tex]

[tex]\rm \: \: 38 - 30 = \bigg[\dfrac{4}{32 - 12 - x} \bigg] \times 10\\[/tex]

[tex]\rm \: \: 8 = \bigg[\dfrac{4}{20 - x} \bigg] \times 10\\[/tex]

[tex]\rm \: \: 2 = \bigg[\dfrac{1}{20 - x} \bigg] \times 10\\[/tex]

[tex]\rm \: \: 1 = \bigg[\dfrac{1}{20 - x} \bigg] \times 5\\[/tex]

[tex]\rm \: 20 - x = 5 \\ [/tex]

[tex]\rm \: - x = 5 - 20\\ [/tex]

[tex]\rm \: - x = - 15 \\ [/tex]

[tex]\bf\implies \:x = 15 \\ \\ [/tex]

[tex]\rule{190pt}{2pt} \\ [/tex]

Additional Information :-

1. Mean using Direct Method

[tex]\boxed{ \rm{ \:Mean = \dfrac{ \sum f_i x_i}{ \sum f_i} \: }} \\ \\ [/tex]

2. Mean using Short Cut Method

[tex]\boxed{ \rm{ \:Mean =A + \dfrac{ \sum f_i d_i}{ \sum f_i} \: }} \\ \\ [/tex]

3. Mean using Step Deviation Method

[tex]\boxed{ \rm{ \:Mean =A + \dfrac{ \sum f_i u_i}{ \sum f_i} \times h \: }} \\ \\ [/tex]

Answer:

Friar Laurence is presented as a holy man who is trusted and respected by the other characters. The Friar's role as the friend and advisor to Romeo and Juliet highlights the conflict between parents and their children within the play.

Explanation:

hope it helps

Answer:

There are eight parts of speech in the English language: noun, pronoun, verb, adjective, adverb, preposition, conjunction, and interjection. The part of speech indicates how the word functions in meaning as well as grammatically within the sentence.

Answer:

noun verb adjective etc

Explanation:

Answer:

Motivation is the state that can maintain students' attention and behavior as well as provides with more energy to needed to lead tasks to completion. Thus, it can help sustain activities over a period of time. In education, motivation can have a variety of effects on students' behavior, preferences, and results.