Collect the photographs of different sports persons in India. Observe and note down their body composition and the body type they belong to.​

Answer:

(a) 52 cards in a Deck

(b) dolphin swam in a pod

(c) school of fish

(d) flock of birds

pls brainliest

Answer:

2x+2x+10+30=180

4x+40=180

4x=180-40

[tex]140 \div 4 = the \: value \: of \: x[/tex]

sin theta =√5/3

cos theta 15/24=2/3

tantheta =√5/2

Assuming that the mass of the largest (M) stone that can be moved by flowing river depends on velocity (v), the density (ρ), and acceleration due to gravity (g) show that (M) varies directly as the

velocity (v), the density (ρ), and acceleration due to gravity (g) show that (M) varies directly as thesixth power of velocity flow (v).

• Let M (proportional to) Va db gc …………. (I)

Let M (proportional to) Va db gc …………. (I)M = kVadbgc, where, k is a proportionality constant

adbgc, where, k is a proportionality constant[M] = [V]a[d]b[g]c

Writing the dimensions of each physical quantity.

M1L0T0 = (L1T-1)a(M1L-3)b(L1T-2)c

M1L0T0 = Mb La - 3b + c T-a - 2c

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)a + c = 3 -------------(iii)

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)a + c = 3 -------------(iii)-a - 2c = 0------------(iv)

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)a + c = 3 -------------(iii)-a - 2c = 0------------(iv)On adding (iii) and (iv)

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)a + c = 3 -------------(iii)-a - 2c = 0------------(iv)On adding (iii) and (iv)-c = 3, Hence, c = - 3.

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)a + c = 3 -------------(iii)-a - 2c = 0------------(iv)On adding (iii) and (iv)-c = 3, Hence, c = - 3.Substituting c = -3 in equation (I),

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)a + c = 3 -------------(iii)-a - 2c = 0------------(iv)On adding (iii) and (iv)-c = 3, Hence, c = - 3.Substituting c = -3 in equation (I),a = 6.

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)a + c = 3 -------------(iii)-a - 2c = 0------------(iv)On adding (iii) and (iv)-c = 3, Hence, c = - 3.Substituting c = -3 in equation (I),a = 6.Thus, M = k V6dg

M1L0T0 = Mb La - 3b + c T-a - 2cOn Comparing the powers on both sides of the above dimensional equation:b = 1, a - 3b + c = 0 Hence, a - 3(1) + c = 0a + c = 3 ------------(i)-a - 2c = 0 ----------(ii)On solving (i) and (ii)a + c = 3 -------------(iii)-a - 2c = 0------------(iv)On adding (iii) and (iv)-c = 3, Hence, c = - 3.Substituting c = -3 in equation (I),a = 6.Thus, M = k V6dg∴ M is proportional to the 6th power of V if the mass of the largest (M) stone that can be moved by flowing river depends (i.e., directly proportional to) on velocity (v), the density (ρ), and acceleration due to gravity (g)

Answer:

From Given:-

since Mass ∝V

a

d

b

g

c

⇒M=kV

a

d

b

g

c

Equating dimensions.

[M

′

]=k[L

1

T

−1

]

a

[ML

−3

]

b

[L

1

T

−2

]

c

⇒ on comparing:-

b=1,a−3b+c=0

⇒a+c=3......(1)

and −a−2c=0......(2)

on solving:-

c=−3 and a=6

∴M=k

g

3

V

6

d

∴ Mass ∝ sixth Power of Velocity