Can you answer this question?"You are sleeping and you're hungry: you have butter,cheese and juice in the fridge, what's the first thing you open?​

Answer:

"School" is not only a word because it decides everybody's future, as we all know that Will Gates, Mukesh Ambani, Ratan Tata has started his journey with School.

In school students not only develop own knowledge but also descipline, communication skills,how to react in society.

School not only develop us mentally but also ,socially, emotionally, physically etc.

School make us responsible

But when a student's enters his or her school he feels not happy, he says I don't want to go school,I want to stay home with my parents and family members but slowly slowly he starts loving his school and at last when his schools study completes. Every students weeps a lot, he feels pain and not happy

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Answer:

The number of tiles required for decorating the wall are 2400

The total cost of the tiles required is Rs.6000

Step-by-step explanation:

The dimension of the wall is given 6m by 4m, which means that the length of the wall is 6m (600cm) and breadth is 4m(400 cm)

The area of the wall=length x breadth=600 x 400=240000 [tex]cm^{2}[/tex]

The dimension of the tile is 10cm by 10cm

The area of one tile=(10x 10)[tex]cm^{2}[/tex]=100[tex]cm^{2}[/tex]

Number of tiles required to decorate the wall=[tex]\frac{240000}{100} =2400[/tex]

The cost of one tile is Rs.2.50

The cost of all the tiles=2.50 x2400= Rs. 6000

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that,

• Length of wall = 6m = 6 × 100 = 600 cm

• Breadth of wall = 4m = 4 × 100 = 400 cm

So,

[tex]\rm \: Area_{(wall)} = Length \times Breadth \\ [/tex]

[tex]\rm \: Area_{(wall)} = 600 \times 400 \\ [/tex]

[tex]\rm\implies \:\boxed{ \rm{ \:Area_{(wall)} = 240000 \: {cm}^{2} \: }} \\ [/tex]

Now,

Side of square tile = 10 cm

So,

[tex]\rm \: Area_{(tile)} = {(side)}^{2} \\ [/tex]

[tex]\rm \: Area_{(tile)} = {10}^{2} \\ [/tex]

[tex]\rm\implies \:\boxed{ \rm{ \:Area_{(tile)} = 100 \: {cm}^{2} \: }} \\ [/tex]

Let assume that number of square tiles of size 10 cm required for decorating a wall 6m x 4m be n.

So,

[tex]\rm \: n \times Area_{(tile)} = Area_{(wall)} \\ [/tex]

[tex]\rm \: n \times 100 = 240000 \\ [/tex]

[tex]\rm\implies \:\boxed{ \rm{ \:n \: = \: 2400 \: }} \\ [/tex]

So, 2400 square tiles of size 10 cm required for decorating a wall 6m x 4m.

Further given that,

[tex]\rm \: Cost \: of \: 1 \: tile \: = \: Rs \: 2.50 \\ [/tex]

So,

[tex]\rm \: Cost \: of \: 2400\: tiles \: = 2400 \times 2.50 = \: Rs \: 6000 \\ [/tex]

[tex]\rule{190pt}{2pt}[/tex]

Additional Information :-

[tex]\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}[/tex]

Answer:

true

Explanation:

Economics is a science of choice. ... According to Robbins economics studies human wants and scarce means which have alternative uses. Scarcity of means in relation to unlimited wants leads to the problem of making a choice. Hence the problem of choice is the central problem of an economy.

Explanation:

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