explain any five differences between nation and nationality​

Answer:

i) 2500 f²

ii) 4444.44 f²

Explanation:

i) each side = 200/4 = 50

area enclosed will be =50×50

2500

ii) if house is used as one side the each side length will be =200/3

area enclosed will be =(200/3)²= 40000/9= 4444.44 f²

#please mark as brainiest #

Given,

Fencing a Backyard: Tina and Shriya have just purchased a purebred German Shepherd, and need to fence in their backyard so the dog can run.

To Find,

(i) What is the maximum rectangular area they can enclose with 200 ft of fencing, if they use fencing material

along all four sides? What are the dimensions of the rectangle?

(ii) What is the maximum area if they use the house as one of the sides? What are the dimensions of this

rectangle?

Solution,

i) We have fencing material that will cover 200 ft.

  Since square is a rectangle with the maximum area,

  Each side = 200 / 4 = 50 ft

  So,

  Area enclosed will be = 50×50 = 2500 ft²

  The rectangle will have dimension of 50 ft by 50 ft.

ii) If house is used as one side the each side length will be = 200/3 ft

   So, Area enclosed = (200/3)² = 40000/9 = 4444.44 ft²

   The rectangle will have dimension of 66.67 ft by 66.67 ft.

Hence, the maximum rectangular area they can enclose with 200 ft of fencing, if they use fencing material along all four sides 2500 ft² and it will have dimension of 50 ft by 50 ft ; the maximum area if they use the house as one of the sides will be 4444.44 ft² and it will have dimension of 66.67 ft by 66.67 ft.

Mostly Insane! .........

Answer:

(i) The x -intercepts are [tex]x=20[/tex] and[tex]x=330[/tex].

(ii) The maximize profit occurs at [tex]$f(175)=-.5 \times(175)^{2}+175 \times(175)-3,300=\12,012.50$\\[/tex]

Step-by-step explanation:

Given :

[tex]p(x)=-0.5 x^{2}+175 x-3300[/tex]

Step 1

Solve p(x) by using quadratic equation,

[tex]-0.5 x^{2}+175 x-3300= 0[/tex]

Multiply both sides of the equation by 10,

[tex](10-0.5 x^{2}+175 x-3300)= 0*10[/tex]

[tex]$-0.5 x^{2} \cdot 10+175 x \cdot 10-3300 \cdot 10=0 \cdot 10$[/tex]

[tex]$-5 x^{2}+1750 x-33000=0$[/tex]

Step 2

Solve with the quadratic formula

[tex]$x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$[/tex]

Put [tex]a=-5,b=1750 and c=-33000[/tex]

[tex]$x_{1,2}=\frac{-1750 \pm \sqrt{1750^{2}-4(-5)(-33000)}}{2(-5)}$[/tex]

[tex]$\sqrt{1750^{2}-4(-5)(-33000)}=1550$[/tex]

[tex]$x_{1,2}=\frac{-1750 \pm 1550}{2(-5)}$[/tex]

Step 3

Separating the solutions, we get

[tex]$x_{1}=\frac{-1750+1550}{2(-5)}$[/tex]

[tex]x_{1} =20[/tex] and

[tex]$x_{2}=\frac{-1750-1550}{2(-5)}$[/tex]

[tex]x_{2} =330[/tex]

Step 4

(ii)The maximum units for maximum profit is realized at the point

[tex]$x=-\frac{b}{2 a}$[/tex]

[tex]$x=-\frac{175}{2 \cdot(-.5)}=175$[/tex]

Maximum profit occurs at

[tex]$f(175)=-.5 \times(175)^{2}+175 \times(175)-3,300[/tex]

[tex]= 12,012.50$[/tex]

The maximize profit occurs at [tex]$f(175)=\$ 12,012.50$[/tex]

Answer:

(i) The x -intercepts are [tex]x=20[/tex] and x=330.

(ii) The maximize profit occurs at [tex]f(175)=-5\times (175)^2+175\times (175) -3,300=2,012.50[/tex]

Step-by-step explanation:

Given :

[tex]p(x)=-0.5x^2+175x-3300[/tex]

Step 1

Solve p(x) by using the quadratic equation,

[tex]-0.5x^2+175x-3300=0[/tex]

Multiply both sides of the equation by 10,

[tex](10-0.5x^2+175x-3300)=0\times 10[/tex]

[tex]-0.5x^2.10+175x.10-3300.10=0.10[/tex]

[tex]-5x^2+1750x-3300=0[/tex]

Step 2

Solve with the quadratic formula

[tex]x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]

Put [tex]a=-5,b=1750[/tex] and [tex]c=-33000[/tex]

[tex]x_{1,2}=\frac{-1750\pm\sqrt{1750^2-4(-5)(-33000)} }{2(-5)}[/tex]

[tex]\sqrt{{1750^2-4(-5)(-33000)} }} =1550[/tex]

 [tex]x_{1,2}=\frac{-1750\pm\ 1550}{2(-5)}[/tex]

Step

Separating the solution, we get

[tex]x_1=\frac{-1750+1550}{2(-5)}[/tex]

[tex]x_1=20[/tex]

[tex]x_2=\frac{-1750-1550}{2(-5)}[/tex]

[tex]x_2=330[/tex]

Step 4

(ii) The maximum units for maximum profit is realized at the point

[tex]x=-\frac{b}{2a}[/tex]

[tex]x=-\frac{175}{2.(-5)} =175[/tex]

Maximum profit occurs at

[tex]f(125)=-.5\times (175)^2+75\times (175)-3,300[/tex]

[tex]=12,012.50[/tex]

The maximum profit occurs at [tex]f(175)=[/tex]$ [tex]12,012.50[/tex]

#SPJ2

Answer:

Nature has endowed Kashmir with implausible beauty and is rightly called as "Paradise on Earth".

Answer:

Nature has endowed Kashmir with implausible beauty and is rightly called as "Paradise on Earth"