What does Sigma rule means​

Answer:

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Step-by-step explanation:

AREA enclosed by the OCTAGON

= AREA OF ABCH + DEFG + CDGH

= [1/2(5+11)4] + [1/2(5+11)4] + (5x11)

= 32 + 32 + 55

= 119m²

AREA OF TRAPEZIUM

= 1/2(sum of parallel sides)

Answer:

The area enclosed by octagonal figure is 119 sq.M

Step-by-step explanation:

Given : Regular octagon side = 5 m

Solution :

Area of regular octagon ABCDEFGH = Area of Trapezium ABCH

                                                               + Area of Trapezium GDFE

                                                               + Area of Rectangle HFDC

Area of Trapezium ABCH = 1/2 x Height x ( Sum of parallel sides)

                                           = 1/2 x AX x( AB + CH)

                                           = 1/2 x 4 x (5+11)

                                           = 1/2 x 4 x 16

                                           = 32 sq.M

Area of Trapezium GDFE = 1/2 x Height x ( Sum of parallel sides)

                                         = 1/2 x YF x ( GD + EF)

                                          = 1/2 x 4 x ( 11 + 5 )

                                          = 1/2 x 4 x 16

                                           = 32 sq.M

Are of rectangle HGDC = Length x Breadth

                                       = HC x CD

                                       = 11 x 5

                                       = 55 sq. M

 Area of regular octagon ABCDEFGH = 32 + 32 + 55

                                                               = 119 sq. M

Answer:

-505 J

Explanation:

The change in the internal energy is given by the following expression.

ΔU=q+W

Since container is well insulated, q=0.

Hence, ΔU=W=−PΔV

ΔU=W=−2.5atm×(4.50L−2.50L)

ΔU=W=−5.0Latm

Convert the unit to J

ΔU=W=−5.0Latm×1Latm101.33J=−505J

The change in the internal energy is given by the following expression.

The change in the internal energy is given by the following expression.ΔU=q+W

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔV

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0Latm

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0LatmConvert the unit to J

The change in the internal energy is given by the following expression.ΔU=q+WSince container is well insulated, q=0.Hence, ΔU=W=−PΔVΔU=W=−2.5atm×(4.50L−2.50L)ΔU=W=−5.0LatmConvert the unit to JΔU=W=−5.0Latm×1Latm101.33J=−505J

Answer:

Joseph I have a lot to do and will be doing some more research for class 4th November as well and the other dates

Answer:

as it has the functional group similar to that of carboxylic acid few properties are almost similar to it.

Explanation:

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