Energy released in the fission of a single 92U235 nucleus is 200 MeV. The fission rate of a 92U235 fuel reactor operating at a power level of 5 W is 1.56×105.5k s−1. The value of k is - 1 2 3 4

Answers 1

Explanation:

power

P

=

n

E

1

t

Where,

n

→

Number of fission reaction

E

1

→

Energy released in a single fission reaction

Fission rate

n

t

=

P

E

1

We know that,

1

MeV

=

1.6

×

10

−

13

J

⇒

n

t

=

5

200

×

1.6

×

10

−

13

⇒

n

t

=

1.56

×

10

11

s

−

1

Given,

n

t

=

1.56

×

10

5.5

k

s

−

1

∴

k

=

2

If you know the answer add it here!

Can't find the answer?

Other related questions that may help you

Geeta said,"rakesh can swim across the river."

Answer:

Step-by-step explanation: Geeta said, "rakesh can swim across the river."

Gita told that Rakesh could swim across the river. Hope it helps you Please mark me as a brainlist
Cos 3a cos a +sin4a sin a =cos a cos 2a

Please mark me as brainliest answer

Find answer in your book

Hope it helps .......

Arrange F, Cl, O, N in the decreasing order of electronegativity O > F > N > Cl F > N > Cl > O Cl > F > N > O F > O > N > Cl

Answer:

option D is correct

Explanation:

hope so it's help u

Why is it useful that the plastic strips break down naturally

Answer:

The plastic strips covering the growing potato plants must be clear so the leaves will get enough . The potato plants grow well because the gaps between the plastic strips will let and get into the soil. (b) The plastic strips break down naturally after a few weeks.

Explanation:

Other Physics Questions

Log in with Google

 or

Forgot your password?

I don't have an account, and I want to Register

Choose a language and a region

English

United States

Polski

Polska

Português

Brasil

English

India

English

Philippines

Español

España

Bahasa Indonesia

Indonesia

Türkçe

Türkiye
How much to ban the user?
1 hour 1 day 100 years