A block is placed on a wet slippery floor.the mass of block is 15 kg.when it is pulled through a string and spring balance it shows force equal to 3N.find the coefficient of friction (Fs=u mg)
Answers 1
Answer:
0.02
Explanation:
Given : F = 3N, m= 15kg, m =15 x 10⁻²g
Formula : f = μmg
Solution :
Here, F is the frictional force, μ is the coefficient of friction, m is the mass of the block.
Frictional force is given by f = μmg
therefore , 3N= 15g * μ
μ = 3/15 x 10⁻² = 0.02μ = 0.02
-
Author:
cowboymqhk
-
Rate an answer:
4
If you know the answer add it here!
Other related questions that may help you
sudheer needs help ascomplete the sentences using conjunction
-
Author:
natalia20
-
Author:
butchpvnc
-
Rate an answer:
1
पेड़- पौधो की कटाई रोकने के लिए नारा (Slogan) लिखिए
-
Author:
averybaker
-
Author:
albertjackson
-
Rate an answer:
3
-
Author:
abelkgtn
-
Rate an answer:
1
2. You accidentally dropped your favourite toy and broke it. This is a change you did not want. Can this change be reversed?
-
Author:
fabian
-
Author:
princesspxeu
-
Rate an answer:
5
-
Author:
lukeaskp
-
Rate an answer:
4
Choose a language and a region
How much to ban the user?
1 hour
1 day
100 years