calculate the concentration of solution when 12 g of glucose is dissolved in 88 g of water​

Answers 1

Answer:

concentration of solution will be 12 %

Explanation:

Mass percent of solute =

( mass of solute/mass of solutions)×100

Mass of solute = 12 g

Mass of solvent = 88 g

Mass of solution = 100 g

(12/100)×100

=12%

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Other related questions that may help you

I care for my studies as much as I care for playing football well use don't​

Answer:

I don't care for my studies as much as I care for playing football

Answer:

i don't care for my studies as much as i care for playing football.

3) The time period of the pendulum is 5s. How many oscillations does it make in 130 s?​

Answer:

For 15 oscillation it takes 30 sec

For one oscillation Tme period = 30/15 = 2sec

Frequency = 1/ Time period

=1/2=0.5 Hz

Answer: The pendulum completes 26 oscillations in 130 sec

Explanation:

Given,

The time period of oscillation (T)= 5 sec

This means the pendulum completes one oscillation in 5 sec

Therefore the number of oscillations in 130 s is given by (n) = [tex]\frac{130}{5} =26[/tex]

∴ The pendulum completes 26 oscillations in 130 sec.

8/7 * 49/64 + 1/2 * 3/4 + 7/8 * (-2/3) Pls answer T-T

Given expression be ;

[tex][\frac{8}{7} *\frac{49}{64} ]+[\frac{1}{2} *\frac{3}{4}] + [\frac{7}{8} *\frac{-2}{3}][/tex]

after solving we get ;

[tex]\frac{7}{8} + \frac{3}{8} + \frac{-7}{12}\\\\\frac{10}{8} + \frac{-7}{12} \\\\\frac{2}{3}[/tex]

So , the answer is    [tex]\frac{2}{3}[/tex]

45y^4+18y^3-4y^2 by 9y^3​

Answer:

Quotient is 5y+2

Remainder is -4y²

Step-by-step explanation:

Hope this will help you.

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