Answer:
Distance=16 km
Displacement=11.31 km
Explanation:
S=8+8=16 km
d=
[tex] \sqrt{ {8}^{2} + {8}^{2} } = \sqrt{64 + 64} = \sqrt{128} = 11.31 \: km [/tex]
[tex]{hyp} = \sqrt{ {base}^{2} + {perpendicular}^{2} } [/tex]
Author:
salvadoryfl7
Rate an answer:
8Answer:
Distance=16 km
Displacement=11.31 km
Explanation:
To Find Distance
S=8+8=16 km
To Find Displacement
d=
\sqrt{ {8}^{2} + {8}^{2} } = \sqrt{64 + 64} = \sqrt{128} = 11.31 \: km
8
2
+8
2
=
64+64
=
128
=11.31km
{hyp} = \sqrt{ {base}^{2} + {perpendicular}^{2} }hyp=
base
2
+perpendicular
2
Author:
anabellahester
Rate an answer:
6