A particle is projected with a velocity 8 m/s at an angle 60° to the horizontal on a level surface . The average velocity of the projective over its time of flight is​

Answers 1

Answer:

Explanation:

Time of flight =  

g

2usinθ

                     =

10

2×80×sin30

o

=8

As particle during journey at t=2sec and at t=6sec will be at same height and hence vertical displacement is zero.

Horizontal displacement =(ucosθ)×(6−2)

                                      =80×

2

3

×4

                                       =160

3

m

∴ Average velocity =  

4

160

3

=40 √3 m/sec

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