Two buses A and B running in same direction with speed 20m/s & 50 m/ss . A third bus C is moving in opposite directions. At the Instant when the separation between the bus A & B 1000m the bus C meets both the buses A & B at Interval of 10 sec. Assuming bus B ahead of A. Find out speed of Bus C..

Answers 1

Answer:

Let their direction of motion of bus A is iˆ then v⃗ A=(20m/s)iˆ

(a) Relative velocity of A w.r.t. B =v⃗ AB=V⃗ A−v⃗ B= (actual velocity of A)-(velocity of B)

=(20m/s)iˆ−(15m/s)iˆ=5m/siˆ

i.e. A is moving with speed 5m/s w.r.t B in iˆ direction.

(b) Relative velocity of B w.r.t A=v⃗ BA=v⃗ B−v⃗ A= (Actual velocity of B)-(velocity of A)

=(15m/s)iˆ−(20m/s)iˆ=(−5m/s)iˆ=(5m/s)(−iˆ)

i.e. B moving in −iˆ direction w.r.t A, at speed 5 m/s

Only 2, 3 and 4.....

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