Two cars moving with speeds 40 km/hr and 80 km/hr respectively with uniform acceleration. How many times the stopping distance of car with 30 km/hr is greater than another car?

Subject:
Physics
Author:
paulinaboone
Created:
1 year ago

Answers 1

Explanation:

−u

=2as

Substituting v=0,u=40 km/hr,s=2 km

0−40

=2×a×2

a=−400km/h

For u=80 km/h,

0−80

=2×(−400)×s

800

6400

=8 km

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Two cars moving with speeds 40 km/hr and 80 km/hr respectively with uniform acceleration. How many times the stopping distance of car with 30 km/hr is greater than another car?​

Answers 1

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Other Physics Questions

Two cars moving with speeds 40 km/hr and 80 km/hr respectively with uniform acceleration. How many times the stopping distance of car with 30 km/hr is greater than another car?