A car turns a corner on a slippery road at a constant speed of 10 m / s. If the coefficient of friction is 0.5 , the minimum radius of the arc in metre in which the car turns is? a.20 b.10 c.5 d.4
Answers 1
Answer:
Given :-- A car turns a corner on a slippery road at a constant speed of 10 m/s.
- The coefficient of friction is 0.5.
- What is the minimum radius of the arc in metre in which the car turns ?
Given :
- Velocity of Car (v) = 10 m/s
- Coefficient of Friction (μ) = 0.5
- Acceleration due to gravity (g) = 10 m/s²
According to the question by using the formula we get,
[tex]\implies \sf\boxed{\bold{v =\: \sqrt{\mu rg}}}\\[/tex]
where,
- v = Velocity
- μ = Coefficient of Friction
- r = Minimum turning radius in metre
- g = Acceleration due to gravity
So, by putting those values we get,
[tex]\implies \sf 10 =\: \sqrt{0.5 \times r \times 10}\\[/tex]
[tex]\implies \sf 10 =\: \sqrt{0.5 \times 10 \times r}\\[/tex]
[tex]\implies \sf 10 =\: \sqrt{5 \times r}\\[/tex]
[tex]\implies \sf (10)^2 =\: 5r\\[/tex]
[tex]\implies \sf (10 \times 10) =\: 5r\\[/tex]
[tex]\implies \sf 100 =\: 5r\\[/tex]
[tex]\implies \sf \dfrac{100}{5} =\: r\\[/tex]
[tex]\implies \sf 20 =\: r\\[/tex]
[tex]\implies \sf\bold{\underline{r =\: 20\: m}}\\[/tex]
[tex]\therefore[/tex] The minimum radius of the arc in metre in which the car turns is 20 metres .
Hence, the correct options is option no (a) 20 m .
-
Author:
juliette
-
Rate an answer:
10