Two points on a travelling wave having frequency 500 Hz and velocity 300m/s are 60^o out of phase, then the minimum distance between the two points is a.0.2 b.0.1 c.0.5 d.0.4
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Subject:
Physics -
Author:
carleefunb -
Created:
1 year ago
Answers 1
Answer:
Wavelength of the wave is:[tex]λ = \frac{v}{f} = \frac{300}{500} = 0.6[/tex]
- 360° phase difference corresponds to a distance of 1 wavelength or
- 360°phase difference corresponds to a distance of 0.6m
- 60°phase difference corresponds to a distance of
0.6/6=0.1 m
b is correct ❤-
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