the photoelectric work function for a metal is 5 eV. Calculate the threshold frequency for the metal.
Answers 2
Answer:
Threshold frequency is 1.2 × 10^15 Hz.
Explanation:
Threshold frequency can be calculated by using the formula,
threshold frequency = work function (in joule)/ planks constant.
So, here change 5ev into joule by multiplying with 1.6 ×10^-19J which will give 8×10^-19J(approx)
and use planks constant, h= 6.6 ×10^-34J (approx)
Put in the above formula and then.. you got your answer.
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Author:
ciscomontgomery
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Answer:
The threshold frequency for the metal is 1.21×10¹⁵Hz.
Explanation:
The threshold frequency is defined as the minimum frequency of the incident radiation below which the photoelectric emission is not possible completely. It is given as,
[tex]\nu_o=\frac{E_o}{h}[/tex] (1)
Where,
ν₀=thereshold frequency
E₀=work function in joules
h=planks constant=6.6×10⁻³⁴ m²kg s⁻¹
The values given in the question are,
[tex]E_o=5\times 1.6\times 10^-^1^9=8\times 10^-^1^9J[/tex] (2)
By placing the value of E₀ and h in equation (1) we get;
[tex]\nu_o=\frac{8\times 10^-^1^9}{6.6\times 10^-^3^4}=1.21\times 10^1^5 Hz[/tex]
Hence, the threshold frequency for the metal is 1.21×10¹⁵Hz.
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Author:
cherishljka
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