consider a peak rectifier fed by a 60-Hz sinusoid having a peak value Vp=100V. Let the load resistance R=10 k ohm. calculate the fraction of cycle during which the diode is conducting. ​

Answers 2

Answer:

the fraction of cycle which diode is conducting is 3.18%

Explanation:

The best I can explain: w Δt ~ √(2Vr/Vp)

 Θ = √(2 X 2/100)

Θ = 0.2 rad or 3.18% of the cycle

the fraction of cycle which diode is conducting is 3.18 %

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