42. Calculate the Equivalent resistance of the circuit.
Answers 2
For resisters in parallel
1/Req = 1/4+1/12 = 4/12 = 1/3
Req = 3
For resisters in series
Req = 3+8 =11
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Author:
karenxhik
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Answer:
The equivalent resistance of the circuit will be 11 Ω.
Explanation:
Resistances can be connected in two different ways in a circuit. The series and parallel connection.
The effective resistance in a circuit if the resistances are connected in a series manner will be,
R = R₁ + R₂
The effective resistance in a circuit if the resistances are connected in a parallel manner will be,
1/R = 1/R₁ + 1/R₂
In the given circuit the resistances of 4 Ω and 12 Ω are connected in a parallel method. So their effective resistance will be:
1/R = 1/4 + 1/12
1/R = (12 + 4) / (12 × 4)
1/R = 16 / 48
R = 48 / 16
R = 3 Ω
This effective resistance of 3 Ω is in a series connection with the 8 Ω resistance.
∴ R = 3 + 8 = 11 Ω
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Author:
karlieogq5
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