A slit of width d is illuminated by white light. For red light (wavelength = 6500A°), first minima obtained is at 60°. then the value of d is nearly a)750nm b)275nm c)260nm d)360nm​

Answers 1

Answer:

Correct option is C)

The position of n

th

dark fringe in Fraunhoffer Diffraction from a single slit is

asinθ = nλ

a=

sinθ

=

sin30

o

1×6.5×10

−7

, (for first min. n = 1)

=

1/2

6.5×10

−7

=13× 10

−7

m =1.3μm.

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