Answer:
Correct option is C)
The position of n
th
dark fringe in Fraunhoffer Diffraction from a single slit is
asinθ = nλ
a=
sinθ
nλ
=
sin30
o
1×6.5×10
−7
, (for first min. n = 1)
=
1/2
6.5×10
−7
=13× 10
−7
m =1.3μm.
Author:
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