if the equation for the displacement of a particle moving along a circular path is given by theta = to 2 t³ + 0.5 where theta is in radius and t is in seconds then the angular acceleration of the particle at t = 2s is(a) 8 rads-2(b) 12rads-2(c) 24rads-2(d) 36rads-2​

Answers 1

Answer:

Correct option is C)

option c 24 rad s

ω=

dt

dq

=

dt

d

(2t

3

+0.5)=6t

2

t=2s,ω=6×2

2

=24rad/s

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