To find,
the Centripetal acceleration of the earth towards the sun.
Solution,
Let us first calculate the time period of earth's one orbit around the sun,
=> Days *Hours*Minutes*seconds
=> (365.26)*(24)*(60)*(60) = 31558464 s
Now, we'll calculate the centripetal acceleration of the earth towards the sun,
a = v²/r = (2πr/T)²/r = 4π²r/T²
Now, taking r = 1.5 x 10¹¹m (approx. value) and T = 31558464 s
we get a = 0.0059 m/s² towards the sun
We know that mass of earth = 5.98 x 10²⁴ kg.
Therefore, the net force will be F=ma = 5.98 x 10²⁴*0.0059
=> F = 3.5 x 10²² N towards the sun
So, the centripetal force is equal to 3.5 x 10²² N and centripetal acceleration is equal to 0.0059 m/s².
Author:
snow whitecn15
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Explanation:
The centripetal acceleration of the Earth is a = V^2/R. The force exerted on the Earth by the sun is Me * a where Me is the mass of the Earth.
Author:
hermioneo7ee
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