The molar heat capacity in a process of a diatomic gas if it does work of Q\4| when a heat of Q is supplied to it is
-
Subject:
Physics -
Author:
augustmcguire -
Created:
1 year ago
Answers 1
Answer:
First law of Thermodynamics we have :-
Q= w+ΔU (1)
where,
Q = Heat supplied to the gas
w = Work done by the gas
ΔU = Change in the internal energy of the gas
Given :-
w= Q/4 (2)
From (1) & (2) we have :-
⟹ΔU= 3Q/4 (3)
Now,
ΔU= nRΔT/ γ−1 (4)
where,
n = No. of moles of gas
ΔT = Change in temperature
R = Universal Gas Constant
γ = Specific heat ratio
For a diatomic gas :-
γ=7/5 ( 5)
Using (3), (4) & (5) we get :-
⟹nΔT= 3Q/ 10R (6)
Also note that :-
Q=nCΔT (7)
where,
C = Molar specific heat for the process
So now replace nΔT in (7) by (6) :-
⟹ 3QC/ 10R =Q
⟹C= 10R/3
Explanation:
-
Author:
skinny minnysoyt
-
Rate an answer:
3
If you know the answer add it here!
Other related questions that may help you
-
Author:
brayan
-
Author:
winniebibr
-
Rate an answer:
0
-
Author:
evelincrosby
-
Rate an answer:
16
-
Author:
devongilbert
-
Author:
mariepkev
-
Rate an answer:
1
-
Author:
kristadonaldson
-
Rate an answer:
1
-
Author:
brennan65
-
Author:
bingotijr
-
Rate an answer:
8
-
Author:
gentry
-
Author:
josafat4vel
-
Rate an answer:
19
-
Author:
jazleneshah
-
Rate an answer:
3