A car starts from rest and moves with uniform acceleration. If it reaches to a velocity of 25 m/s in 5 seconds, calculate acceleration and distance covered by it in given time.​

Answers 2

Answer:

ut+(1/2)at

2

=0+

2

1

×5×8

2

=160 m.

The velocity attained in 8 seconds is given by

v=u+at

=0+5×8=40 m/s.

The distance traveled in the next 4 seconds is

s

2

=40×4=160 m.

So, the total distance traveled by the car is s

1

+s

2

=160+160=320 m

320

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