A cricketer can throw a ball to a maximum height of 50 m calculate the initial velocity

Answers 1

Answer:

We know that horizontal range is maximum if the angle of projection is 45o and is given by

Rmax = u2 / g

Here, Rmax = 100 m

so, u2 / g = 100 m

If the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the ground

Max = u2 / 2g = 100 /2 = 50 m

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