solve the pair of linear equations x-2y=0 and 3x+4y=20​

Answers 1

3x+4y=20

x=20-4y/3

x-2y=0

20-4y/3-2y=0

Y=6

now put this value in 1st eqn

x-2y=0

x-12=0

x=12

Step-by-step explanation:

X=12,y=6

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If 1kg fish is of 150 rs so what will be the amount if I bought 1kg 700 g fish
[tex]1 \: kg \: \: = 150 \\ \\ 1 \: kg = 1000 \: g \\ \\ = \frac{1000}{150} \\ \\ = 6.67[/tex][tex] \\ [/tex][tex]1 \: kg \: 700 \: g \\ \\ = \frac{1700}{6.67} \\ \\ = 254.8 \: \: rs[/tex]

Step-by-step explanation:

1kg is 1000g.

1000 g is ₹150/-

100g is ₹15

700g is 15 x 7 =105 rs

1kg 700g = 150 + 105 = 255

Thus 1kg 700g of fish is ₹255/-

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Answer:

kuiki wah chote gaon se thi

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