Step-by-step explanation:
Let, the total work be 100 units
Hence, (2/5) × 100 = 40 units
A can do 40 units in 10 days
Also, (1/3)× 100 = 50 units
B can do 50 units in 10days
Efficiency of A = 40/10 = 4 units/day
Efficiency of B = 50/10 = 5 units/day
Efficiency of (A + B) = 9 units/day
They both work together for 5 days
Work done in 5 days = 9 units/day × 5 days = 45 units
Remaining work = Total work – Work done
⇒ Remaining work = 100 – 45 = 55 units
Time taken to complete the work alone = 55/ 5 = 11 days
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