a park is 25 whole 4 upon 5 m long and 20 whole 2 upon 3 m wide find its perimeter if a walkway is to be constructed inside the park which is two whole three upon 8 m wide what would be the inside perimeter of the world​

Answer:

inside perimeter of the walkway = 75 14/15 m

Step-by-step explanation:

Given :  a park is 25 4/5 m long and 20 2/3 m wide . a walkway is to be constructed inside the park which is 2 3/8m wide,

To find : perimeter of park  

inside perimeter of the walkway

Solution:

Park length  25 4/5 m  = 25 + 4/5  m =  (125 + 4)/5 = 129/5 m

Park Width =  20 2/3 m = 20 + 2/3 m = (60 + 2)/3  = 62/3  m

Park perimeter = 2 ( Length + Width )

= 2 ( 129/5  + 62/3)

= 2( 387  + 310)/15

= 2(697)/15

= 1394 / 15

= 92  14/15  m

walkway is to be constructed inside the park which is 2 3/8m wide

2  + 3/8  m   = 19/8  Meter

8 times the width will be reduced  

8 * 19/8   = 19 m

inside perimeter of the walkway  = 92  14/15  - 19

= 75 14/15 m

Park perimeter =  92  14/15  m

inside perimeter of the walkway  = 75 14/15 m

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Answer:

inside perimeter of the walkway = 75 14/15 m

Step-by-step explanation:

Given :  a park is 25 4/5 m long and 20 2/3 m wide . a walkway is to be constructed inside the park which is 2 3/8m wide,

To find : perimeter of park  

inside perimeter of the walkway

Solution:

Park length  25 4/5 m  = 25 + 4/5  m =  (125 + 4)/5 = 129/5 m

Park Width =  20 2/3 m = 20 + 2/3 m = (60 + 2)/3  = 62/3  m

Park perimeter = 2 ( Length + Width )

= 2 ( 129/5  + 62/3)

= 2( 387  + 310)/15

= 2(697)/15

= 1394 / 15

= 92  14/15  m

walkway is to be constructed inside the park which is 2 3/8m wide

2  + 3/8  m   = 19/8  Meter

8 times the width will be reduced  

8 * 19/8   = 19 m

inside perimeter of the walkway  = 92  14/15  - 19

= 75 14/15 m

Park perimeter =  92  14/15  m

inside perimeter of the walkway  = 75 14/15 m