class 9 th find area of triangle 8,5,3

Answers 1

Answer:

Step-by-step explanation:

Let a,b,c be the sides of the given triangle and 2s be its perimeter such that

a=8 cm, b=5 cm and c=3 cm

Now, a+b+c=2s

8+5+3=16

2s=16

s=16/2

s=8

Therefore,

s−a=8−8=0,

s−b=8-5=3,

s−c=8-3=5.

Hence the area of the given triangle,

[tex]\sqrt{ s(s-a)(s-b)(s-c)[/tex]

0 is the answer.

simplify 54.16-[11.2+6 of (13-0.5*4.02)

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