Let E1 and E2 be two ellipses whose centers are at origin. The major axes of E1 and E2 lie along the x - axis and y - axis, respectively. Let S be the circle x^2 + (y - 1)^2 = 2. The straight line x + y = 3 touches the curves S, E1 and E2 at P, Q and R , respectively. Suppose that PQ = PR = 2(2)3 . If e1 and e2 are the eccentricities of E1 and E2 , respectively then the correct expression(s) is (are) a.e1^2 + e2^2 = 4340 b.e1e2 = (7)2(10) c.|e1^2 - e2^2| = 58 d.e1e2 = (3)4

Answers 1

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Frame Question for the following solutions given below. 1. Number of Maruti cars in Delhi Number of Honda city cars in Delhi Number of Santro cars in Delhi Total numbers of cars in Delhi Number of Primary teachers in India Number of Secondary teachers in India Number of Sr. Secondary teachers in India Total number of teachers in India 3. Wheat produced in 1996 15,00,850 tonne 18,00,000 tonne Wheat produced in 1997 = Increase in production = 18,00,000-15,00,850 = 2,99,150 tonne: 42 2. || || || || || || || || || = 65,43,216 65,321 + 16,34,456 82,42,993 16,96,950 8,26,168 + 5,00,675 30,23,793​

Answer:

Frame question for the following solutions given below:

1. Number of Maruti cars in Delhi

65,43,216

Number of Honda city cars in Delhi

65,321

Number of Santro cars in Delhi

* 16,34,456

Total numbers of cars in Delhi

82,42,993

11 This is your answer I hope guys

Suitable articles? Ravi is .......... University scholar.

Answer:

Ravi is a University scholar.

Answer:

Ravi is a university scholar.

Explanation:

  • The phonetic quality of the first letter of a word is used to determine the article.
  • You use an if the first letter creates a vowel-like sound, and a if the first letter makes a consonant-like sound.
  • When the letter U sounds like the letter Y in YOU, the article a is used in front of it. For example:
  1. A unicorn
  2. A universe
  3. A used tissue
  4. A unique

Conclusion:

Ravi is a university scholar.

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When a chalk stick is dipped in ink, then a.the colored pigments in the ink get absorbed in the chalk. b.the solvent get adsorbed at the surface of chalk. c.inside of the chalk will remain as white while the surface will have colored pigments. d.inside of the chalk will have colored pigments while the surface will remain white.

Answer:

(c)inside of the chalk will remain as white while the surface will have colored pigments.

Explanation:

solute of ink gets absorbed but solvent gets absorbed in calk

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Which of the following pairs constitutes a buffer? a.HNO2 and NaNO2 b.NaOH and NaCl c.HNO3 and NH4NO3 d.HCl and KCl

Answer:

(d) HNO₂ and NaNO₂

Explanation:

(d) HNO₂ and NaNO₂

HNO2 is weak acid and NaNO2 is a salt formed by the combination of weak acid HNO2 and a strong base NaOH. So HNO2 and NaNO2 can be used as buffer. Option D is the answer.

Answer:

(a) HNO2 and NaNO2

Explanation:

Acidic buffer solutions are commonly made by weak acid and one of its salt with strong base and these have pH value less then 7. HNO2 is a weak acid and NaNO2 is its salt with strong base.

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