Answer:
Q.1.
1.Given details are,
Principal (p) = Rs 3000
Rate (r) = 5%
Time = 2years
Interest for the first year = (3000×5×1)/100 = 150
Amount at the end of first year = Rs 3000 + 300 = Rs 3150
Principal interest for the second year = (3150×5×1)/100 = 157.5
Amount at the end of second year = Rs 3150 + 157.5 = Rs 3307.5
∴ Compound Interest = Rs 3307.5 – Rs 3000 = Rs 307.5
Given details are,
Principal (p) = Rs 3000
Rate (r) = 5%
Time = 2years
Interest for the first year = (3000×5×1)/100 = 150
Amount at the end of first year = Rs 3000 + 300 = Rs 3150
Principal interest for the second year = (3150×5×1)/100 = 157.5
Amount at the end of second year = Rs 3150 + 157.5 = Rs 3307.5
∴ Compound Interest = Rs 3307.5 – Rs 3000 = Rs 307.5
2.Here, P= Rs. 8000,R=10% per annum and n=3 years
Using the formula, A=P(1+100R)n
Amount after 3 years =8000×(1+10010)3
=8000×1011×1011×1011
=10648
Thus, amount after 3 years = Rs. 1648.
And compound interest = Rs. (10648−8000)=2648.
Q,2
1. P = ₹27000 ; R = 10% ; T = 1 year
I = prt/100
= ₹27000×10×1/100
= ₹2700
Amount = ₹(27000 + 2700)
= ₹29700
Step-by-step explanation:
