If[tex]y = {tan}^{ - 1} ( \frac{1 - {x}^{2} }{1 + {x}^{2} } )[/tex], then find [tex] \frac{dy}{dx} \: at \: x \: = 1[/tex]​

Answers 2

Answer:

1

Step-by-step explanation:

We have,

t+1/t = 8

Taking cube on both sides we get

(t+1/t)³= 8³

expanding left hand side of the equation using a + b whole cube formula we get

(t+1/t)³= t³+ 1/t³+ 3t*1/t (t+1/t)

Therefore,

8³ = t³+1 /t³+3(t+1/t)

⇒ 8³ = t³+1 /t³+3(8)

8³ = t³+1 /t³+ 24

8³-24= t³+1 /t³

512-24= t³+1 /t³

488 = t³+1 /t³

Thus the value of t³+1 /t³ is 1

Step-by-step explanation:

Using divisibility test, check whether the following are divisible by 11:

1. 990

2. 6686

3. 4098

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