1. Find the median and mode of the following data. 16, 23, 18, 13, 15, 20, 19, 11, 14. 16​

Answers 1

Answer:

median 16

mode 16

Step-by-step explanation:

middle term (16+16)÷2=16

mode (repeated term)=16

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lcm of 39,45 and 54 following by divison method

Step-by-step explanation:

The least common multiple of 39, 45 and 54 is 3510.

39 => 3 x 13

39 => 3 x 1345 => 3 x 3 x 5

39 => 3 x 1345 => 3 x 3 x 554 => 2 x 3 x 3 x 3

39 => 3 x 1345 => 3 x 3 x 554 => 2 x 3 x 3 x 3= 3 x 3 x 13 x 5 x 2 x 3

39 => 3 x 1345 => 3 x 3 x 554 => 2 x 3 x 3 x 3= 3 x 3 x 13 x 5 x 2 x 3= 3510

39 => 3 x 1345 => 3 x 3 x 554 => 2 x 3 x 3 x 3= 3 x 3 x 13 x 5 x 2 x 3= 3510lcm (39, 45 and 54) = 3510

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Answer:

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the following are the weights (in kg wt) of 8 students 49.3,43,51.2,49.5,50.2,45,45.5,48.3 1) find the mean weight 2) how many students have weights than mean weight 3)if a student whose weight is 59 wt also includes,then what will be the mean weight ?​

Answer:

  1. 47.75
  2. 5 students have weights greater than mean weight and 3 students have weight lesser than mean weight.
  3. 49

Step-by-step explanation:

  1. 49.3+43+51.2+49.5+50.2+45+45.5+48.3

8

=382 /8

=47.75

the mean weight is 47.75

2. 5 students have weights greater than mean weight and 3 students have weight lesser than mean weight.

3. 49.3+43+51.2+49.5+50.2+45+45.5+48.3+59 ÷ 9

= 49

If a student whose weight is 59 wt also includes,then the mean weight will be 49.

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