The average ages 4 member each having the age difference of 2yrs is 54 yrs .what is the sumof the youngest and oldest family members

Answers 2

Answer:

108

Step-by-step explanation:

Ages of the 4 members = 51, 53, 55 and 57

Age of youngest member = 51

Age of oldest member= 57

Sum of the youngest and oldest family members= 51 + 57= 108

Answer:

Total age of Four members =54×4=216

Let the age of first peron be x

Age of second person = x+2

Age of third person = x+4

Age of Fourth person = x+6

So 4x+12=216→x=51

Age of youngest member = 51 Years

Age of oldest member = 57 years

Sum of ages of both = 51+57=108 years

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answer is (2b+5) and (b+0) that is b=-5/2 and b=0

Step-by-step explanation:

2b²+5b=0

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